(3x+9)/(x^2-9)

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Solution for (3x+9)/(x^2-9) equation: 


D( x )

x^2-9 = 0

x^2-9 = 0

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

(3*x+9)/(x^2-9) = 0

3*x+9 = 0 // - 9

3*x = -9 // : 3

x = -9/3

x = -3

x in { -3} 

x belongs to the empty set

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